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2=(8+a^2)/12
We move all terms to the left:
2-((8+a^2)/12)=0
We multiply all the terms by the denominator
-((8+a^2)+2*12)=0
We calculate terms in parentheses: -((8+a^2)+2*12), so:We get rid of parentheses
(8+a^2)+2*12
We add all the numbers together, and all the variables
(8+a^2)+24
We get rid of parentheses
a^2+8+24
We add all the numbers together, and all the variables
a^2+32
Back to the equation:
-(a^2+32)
-a^2-32=0
We add all the numbers together, and all the variables
-1a^2-32=0
a = -1; b = 0; c = -32;
Δ = b2-4ac
Δ = 02-4·(-1)·(-32)
Δ = -128
Delta is less than zero, so there is no solution for the equation
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